We have been learning about three ways to find meaning in a set of data: the mean, median and mode. Each one has their uses; each one helps us find a pattern in a group of numbers. Mathematics is the science of finding patterns.
As human beings we try to make sense of the world around us by finding patterns and using those patterns to help us navigate in the world; traffic lights change from green to yellow then red.; we use this pattern to stay safe as a driver.
In the fall temperatures begin to drop; this pattern allows us to make decisions about clothing, food etc. Our activity today will further explore using mean, median and mode to find a pattern.
Problem 1.: A typical fall day in Hartford
During the last month the temperature has reached: 70, 55, 82, 77, 84, 65, 48. Find the mean median and mode and based on that information describe a typical October day in Hartford.
Problem 2: Use the internet to find the daily temperatures in Hartford during 7 days in July. Find the mean, median and mode and describe a typical day in Hartford in July.
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31 comments:
This is how you answer the question.
68.71 is the mean
70 is the median
There is no mode
mean=68.7
median=77
there is no mode
mean:68.7
median:77
there is no mode
mean:68
median:70
mode:thier iz none
a typical day in da fall iz . kinda hot but windy so it would be smart 2 dress heavy but not 2 heavy. like a sweater would be god 2 wear on a typical day inda fall..!!
Problem #1
mean=68.71
median=70
mode=0
Problem #2
A typical day in hartford according to the tempurturs given was rather warm there was cold day but for the most part it was warm the average was 68.7.This is important because you wouldnt want to go out in the cold with shorts it good to know how cold or hot it is it may determain the outcome of your day.
mean: 68.71
no mode
median:70
hi mr.gengle
mean: 68.71
no mode
median:70
A typical day in hartford according to the tempurturs given was rather warm there was cold day but for the most part it was warm the average was 68.7.This is important because you wouldnt want to go out in the cold with shorts it good to know how cold or hot it is it may determain the outcome of your day.
M3AN=488
M3DIAN=70
MOD3=36
M3AN=530
M3DIAN=74
MOD3=24
the mean is 68.71 or 68
the median is 70
there is no mode
the average temperature in july is between 84 and 65
median=70
mean=68.7
mode=none
&& the weather 4 october is confused it dOnt no if it wanna be cOld Or hOt....
mean=68.7
median=77
there is no mode
well if you put your #s that r in the problem from least 2 greatest dan this wil be ur awnser...
70=ur median
no=ur mode
68.5=ur mean
mean: 68.71
no mode
median:70
the mean is 68.9
the median is 70
there is no mode
A typical Fall day in Hartford would be about 70 degrees. It's going to be sunny but windy, so make sure you dress warm.
mean-68.7
median-70
mode-0
mean=68.7
median=70
mode=none
a typical day in hartford in october is about 69 so that is important because so that people know whats the proper clothing to wear.
ther iz no mode
the median iz 70
the mean iz 68.71
tH3 M3AN iS [[69]]
M3DiAN iS [[70]]
MOD3 = tH3R3 iS NO MOD3
TH3 AV3RAG3 t3MP3RtUR3 ON A tyPiCAL FALL DAy iS ABOUt 70 D3GR33S iT MiGHt B3 A LittL3 WiNDy SO yOU MiGHt WANt tO W3Ar A SW3At3R oR SOM3thiNG tHAT yOU CAN R3MOV3 iN CASE yOU G3t A LiTTl3 CHiLLy OR tOO HOt...
POST3D BY tH3 B3St ╚»3RiCA AKA B3BA«╝
HAT3 ON iT!
well da answer for q#2 if u look up from july1-july7 the tempertures were 84.82.87..73.75.81.and84 putting these # from least 2 greatest give u dese answers...
82=median
84=mode
80.8=mean
MEAN:68.7
MEDIAN:70
MODE:none
A typical day in october and hartford is ABOUT 68.7. THIS IS IMPORTANT BEACUSE WE NEED TO KNOW WAT WERE GOING TO WEAR AND IS U ARE PLANING SOME SORT OF ACTIVITY U NEED TO U KNOW IF U CAN DO IT INDOORS OR OUT DOORS
there iz no mode
the median iz 73
the mean iz 72.9
da typicl day in hartford in july
between 63-84
Mean:68.7
Median:77
Mode:none
A typical day in Hartford with temperatures of "68.7"
Is a good day to be outside with a sweater just for the lovly wind,mostlikly to rain or just dark clouds.
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